Question

Calculati log12 18+log12 8

Answer 1

$log_{12}18+log_{12}8=log_{12}(8*18)=log_{12}144=2$

Answer 2

$\displaystyle log_{12}18+log_{12}8=log_{12}(18 \cdot 8)=log_{12}144=log_{12}12^2=2log_{12}12=2 \\ \\ \boxed{log_ax+log_ay=log_a(x \cdot y)}$