Question

calculati log3[log2(log2 256)] ;log 1 pe 3 la puterea 3 √81;log25 la puterea 3 √1supra 5

Answer 1

a)$log_{3}( log_{2}256)= log_{3}( log_{2}2^8)= log_{3}8=3 log_{3}2$
b)$log_{ \frac{1}{3} 3^{ \sqrt{81} } }= log_{ \frac{1}{3}3^9 }=9 log_{ \frac{1}{3} 3}=-9$