Question

Calculati lungimea segmentului AB unde:
a)A(-1,0);B(3,0)
b)A(-1.0);B(5,0)
c)A(0,-2);B(0,1)
d)A(0,2);B(0,5)
e)A(12,0);B(0.5)
f)A(-3,0);B(0,4)
g)A(-1,1);B(0,3)
h)A(-3,-2);B(1,1)
i)A(0,0);B(6,8).

Answer 1

a)A(-1,0);B(3,0)
AB=I-1I+3=1+3=4

b)A(-1.0);B(5,0)
AB=I-1I+5=1+5=6

c)A(0,-2);B(0,1)
AB=I-2I+1=2+1=3

d)A(0,2);B(0,5)
AB=2+5=7

e)A(12,0);B(0.5)
AB=√(12²+5²)=√(144+25)=√169=13

f)A(-3,0);B(0,4)
AB=√(I-3I²+4²)=√(9+16)=√25=5

g)A(-1,1);B(0,3)
AB=√(3-1)²+I-1I²)=√(2²+1)=√5≈2,236

h)A(-3,-2);B(1,1) 
AB=√(I-3I+1)²+(I-2I+1)²)=√(4²+3²)=√(16+9)=√25=5

i)A(0,0);B(6,8)
AB=√(0+6)²+(0+8)²)=√(36+64)=√100=10