Question

Calculati masa a 448 litri conditii normale deAc=12 ,Ao=16

Answer 1

n=V/Vu

n-nr. de moli
V-volum oarecare
Vu-volum molar=22,4 L

n=448 L/22,4L pe mol=20moli

n=m/mu

m-masa oarecare
mu=masa moleculara

=>m=n•mu=20 moli• 28g/mol=560g(CO)
=20 moli•44g/mol=880g(CO2)