Question

Calculati masa de cloroform (în kg) care se obține din 56 cm3 metan de puritate 80% dacă au loc pierderi de 30%.

Answer 1

CH4 + 3 Cl2 => CHCl3 + 3 HCl
V pur = V total*puritatea/100 = 56*80/100 = 44.8 cm3
V reactionat = V pur - 0,3 * V pur
V reactionat = 44,8 - 0,3 * 44,8 = 31,36 cm3
22,4 l CH4...........119.5 g CHCl3
31,36 cm3 CH4..............x mg CHCl3
x = 167.3 mg cloroform

Answer 2

puritatea = V pur / V impur *100 => Vpur=80*56/100=44,8cm³ CH₄ = 

30/100*44,8=13,44cm³ CH₄ care se pierde

ramas => 44,8-13,44=31,36cm³

CH₄ + 3Cl₂ = CHCl₃ + 3HCl

22,4cm³ CH₄................119,5mg CHCl₃
31,36cm³ CH₄..............x=167,3mg CHCl₃

167,3mg=167,3*10⁻⁶ kg CHCl₃