Question

calculati masa de iodura de potasiu care trebuie adaugata in 100 de gramr dr solutie in azotat de olumb cu concebreatia procentuala​

Answer 1

Răspuns:

ms=100g

C=5%

md=?

md=Cxms/100=5x100/100=5g Pb(NO3)2

MKI=39+127=166g/mol

MPb(NO3)2=207+2x14+6x16=331g/mol

2x166g....331g

2KI   +  Pb(NO3)2→2 KNO3  + PbI2

xg.............5g

x=5x2x166/331=calculeaza

Explicație: