Question

Calculati masa de plumb depus si numarul de moli de sare rezultata din reactia zincului cu 200g solutie de azotat de plumb de concentratie 10%

Answer 1

Cp=md/ms*100==>md=Cp*ms/100=10*200/100=20g Pb(NO3)2

MPb(NO3)2=331g/mol

MZn=65g/mol
MZn(NO3)2=189g/mol

65g.....331g..............189g..........207g
Zn + Pb(NO3)2 --> Zn(NO3)2 + Pb
x=3.927g....20g......y=11.5g

n=m/M=11.5/189=0.06 moli Zn(NO3)2