Question

Calculati masa de solutie de HCl 18,25% care se consuma in reactia cu 200g de CaCO3 si volumul gazului degajat.

Answer 1

CaCO3 + 2HCl --> CaCl2 + CO2 + H2O

100g CaCo3.....73g HCl...111g CaCl2...44g CO2..18g H2O
200g CaCo3...x=146g HCl...y=222g CaCl2...z=88g CO2

Cp=md/ms*100==>ms=md*100/Cp=146*100/18.25=800g HCl

n=m/M=88/44=2 moli CO2

n=V/Vmolar==>V=n*Vmolar=2*22.4=44.8 L CO2 (gaz)

MCaCO3=100g/mol
MCaCl2=111g/mol
MCO2=44g/mol
MHCl=36.5g/mol