Question

Calculati masa de solutie de NaOHde concentratie 20 %care reactioneaza cu 320 g CuSO4

Answer 1

2NaOH + CuSO₄ -> Cu(OH)₂ + Na₂SO₄

2x40g NaOH.............160g CuSO₄ (M NaOH=40g/mol ; M CuSO₄=160g/mol)
xg NaOH..............320g CuSO₄
=>x=320x2x40/160=160 g NaOH (md)

c=100md/ms => ms =100md/c => ms=100x160/20=800g solutie NaOH de c=20%

Answer 2

[tex]~~~~40~~~~~~~~~~160\\2NaOH+CuSO_4=Cu(OH)_2+Na_2SO_4\\ ~~~~x~~~~~~~~~~~320\\\\ M_N_a_O_H=A_N_a+A_O+A_H\\ ~~~~~~~~~~~~=23+16+1\\ ~~~~~~~~~~~~=40\\ 1mol~NaOH=40g\\\\ M_C_u_S_O__4=A_C_u+A_S+A_O*4=64+32+16*4=160\\ [/tex][tex]1mol~CuSO_4=160g\\\\ \frac{2*40}{x}= \frac{160}{320} =\ \textgreater \ x= \frac{320*80}{160} =\ \textgreater \ x=160gNaOH\\\\ m_s= \frac{160*100}{20} = \frac{16000}{20} =800g(solutie~NaOH)[/tex]