Question

Calculati masa impura HgO. pHgO=80% si mO2=95g

Answer 1

2HgO=2Hg+O2
M O2=2AO=32g/mol => n O2=95/32=2,96875moli

2moli HgO....1mol O2
x.....2,96875
x=5,9375moli HgO
M HgO=A Hg+ AO=217g/mol=>m pura HgO=5,9375*217=1288,4375g

p=m pura*100/(m pura+m impura)

0,8=1288,4375/(1288,4375+ m imp)
m imp=322,1093g