Question

Calculati masa molara medie a amestecului format din 2 moli de O2; 2,24L de H2; 44g CO2 si 6,023*10^23 molecule de N2.

Answer 1

Niu (H2)=2.24l÷22.4l/mol=0.1mol
Niu (CO2)=44g÷44g/mol=1 mol
Niu (N2)=6.023×10'23molec.÷6.023×10'23molec./mol=1mol
m (O2)=2mol×32g/mol=64g
m (H2)=0.1 mol×2g/mol=0.2g
m (N2)=1mol×28g/mol=28g
m (tot)= 44+28+0.2+64=136.2g
Niu (tot)=2+0.1+1+1=4.1mol
M (med)=136.2g÷4.1mol=33g/mol