Question

Calculati masa moleculara a oxidului de. Litiu,oxid de potasiu,oxid de calciu,oxid de magneziu,oxid de aluminiului,oxid de fier

Answer 1

LiO = oxid de litiu

A(Li) = 7, A(O) = 16

M = 1x7+1x16 = 23 g/mol

K2O = oxid de potasiu

A(K) = 39, A(O) = 16

M = 2x39+1x16 = 94 g/mol

CaO = oxid de calciu

A(Ca) = 40, A(O) = 16

M = 1x40+1x16 = 56 g/mol

MgO = oxid de magneziu

A(Mg) = 24, A(O) = 16

M = 1x24+1x16 = 40 g/mol

Al2O3 = oxid de aluminiu

A(Al) = 27, A(O) = 16

M = 2x27+3x16 = 102 g/mol

FeO = oxid de II

A(Fe) = 56, A(O) = 16

M = 1x56+1x16 = 72 g/mol

sau

Fe2O3 = oxid de III

A(Fe) = 56, A(O) = 16

M = 2x56+3x16 = 160 g/mol