Question

Calculati masa moleculara relativa pentru fiecare substanta:e)glucoza C6H12O6 f)zaharul C12H22O11 g)iodul l2 h)cretaCaCO3 i)varul stins Ca(OH)2 va rog

Answer 1

C6H12O6=12*6+1*12+16*6=180
C12H22O11=12*12+1*22+16*11=342
I2=127*2=254
CaCO3=40*1+12*1+16*3=100
Ca(OH)2=40*1+(16+1)*2=74