Question

Calculati masa solutiei de metanol de concentratie 20% obtinuta din 448 l cn metan de puritate 90% la un randament al reactiei de 80%

Answer 1

0,9*448=403,2 L CH4 pur

n=V/Vm=403,2/22,4=18 moli CH4

CH4 + 1/2O2 => CH3-OH

nt=18*100/80=22,5 moli CH4

nCH4=nCH3-OH = 22,5 moli

md CH3-OH = 32*22,5=720g

C=md/ms*100=>ms=md*100/C=72000/20=3600g sol alcool