Question

Calculati masele moleculare ale substantelor; Cu(OH)2,,,H2CO3...HI...SO2....KCl...P2O5...NaOH...NHO2...NaBr...CuS///////va rog ,,,dau coroana

Answer 1

Oxizi                                            Baze

SO2   dioxid de S                         Cu(OH)2        hidroxid cupric
P2O5 pentoxid de fosfor               NaOH             hidroxid de Na


Acizi                                                        Saruri

H2CO3      acid carbonic                         KCl    clorura de K
HI               acid iodhidric                        NaBr    bromura de  Na
HNO2         acid azotos                           CuS   sulfura cuprica


MSO2=32+2.16=64
MP2O5=2.31+5.16=142
MCu(OH)2=64+2.16+2=98
MNaOH=23+16+1=40
MH2CO3=2+12+3.16=62
MHI=1+127=128
MHNO2=1+14+2.16=47
MKCl=39+35,5=74,5
MNaBr=23+80=103
MCuS=64+32=96

Answer 2

M Cu(OH)2=64+16*2+1*2=98 g/mol
M H2CO3=1*2+12+16*3=62 g/mol
M HI=1+127=128 g/mol
M SO2=32+16*2=64 g/mol
M KCl=39+35,5=74,5 g/mol
M P2O5=31*2+16*5=142 g/mol
M NaOH=23+16+1=40 g/mol
M NHO2=14+1+16*2=87 g/mol
M NaBr=23+80=103 g/mol
M CuS=64+32=96 g/mol