Question

Calculati masele moleculare pentru compusii de mai jos. Folositi masele atomice din anexa.
M K2O=
M Ca(OH)2=
M CaCO3=
M NaNO3=
M K2SO3=
M Ca(NO3)2=
M H2SO4=
M Al(OH)3=
M Na3PO4=
M (NH4)2SO4=
Va rog frumos ajutatima cat mai repede posibil!

Answer 1

M(K2O)=39*2+16=94 g/mol
M Ca(OH)2=40+16*2+1*2=74 g/mol
M(CaCO3)=40+12+16*3=100 g/mol
M(NaNO3)=23+14+16*3=115 g/mol
M(K2SO4)=39*2+32+16*4=174 g/mol
M Ca(NO3)2=40+2*14+16*6=164 g/mol
M (H2SO4)=1*2+32+16*4=98 g/mol
M Al(OH)3=27+16*3+1*3=78 g/mol
M(Na3PO4)=23*3+31+16*4=164 g/mol
M (NH4)2SO4=2*14+1*8+32+16*4=132 g/mol

Answer 2

MK2O=Ak+2oriAo
=39+2ori16
=39+32
=71
MCa(OH)2=Aca+2oriAo+2oriAh
=40+2ori16+2ori1
=40+32+2
=74
MCaCO3=Aca+Ac+3oriAo
=40+12+3ori16
=40+12+48
=100
MNaNO3=Ana+An+3oriAo
=23+14+3ori16
=24+14+48
=86
MK2SO3=2oriAk+As+3oriAo
=2ori39+32+3ori16
=78+32+48
=158
MCa(NO3)2=Aca+2oriAn+6oriAo
=40+2ori14+6ori16
=40+28+96
=164
MH2SO4=2oriAh+As+4oriAo
=2ori1+32+4ori16
=2+32+64
=98
MAl(OH)3=Aal+3oriAo+3oriAh
=27+3ori16+3ori1
=27+48+3
=78
MNa3PO4=3oriAna+Ap+4oriAo
=3ori23+31+4ori16
=69+31+64
=164
M(NH4)2SO4=4oriAn+8oriAh+As+4oriAo
=4ori14+8ori1+32+4ori16
=56+8+32+64
=160

Sper ca te am ajutat