Question

Calculati masele moleculare si molul urmatoarelor substante:
MH2O=
MH2SO4=
MCa(OH)2=
MNH3=
MHNO3=
MCaCO3=
MCuSO4=
MNaOH=
MHCl=
MAl2O3=
MMg(OH)2=
MNaNO3=
MSO3=
MH3PO4=
MCO2=
MH2O2=
MCu(OH)2=
MAl2S3=
MH2CO3=
MAlCl3=
MP2O5=

Answer 1

$M_{H_2O}=2+16=18\ g/mol \\ M_{H_2SO_4}=2+32+64=98\ g/mol \\ M_{Ca(OH)_2}=40+32+2=74\ g/mol \\ M_{NH_3}=14+3=17\ g/mol \\ M_{HNO_3}=1+14+48=63\ g/mol \\ M_{CaCO_3}=40+12+48=100\ g/mol$
[tex]M_{CuSO_4}=66+32+64=162\ g/mol \\ M_{NaOH}=23+16+1=40\ g/mol \\ M_{HCl}=1+35.5=36.5\ g/mol \\ M_{Al_2O_3}=54+48=102\ g/mol \\ M_{Mg(OH)_2}=24+32+2=58\ g/mol \\ M_{NaNO_3}=23+14+48=85\ g/mol \\ M_{SO_3}=32+48=80\ g/mol \\ M_{H_3PO_4}=3+31+64=98\ g/mol \\ M_{CO_2}=12+32=44\ g/mol \\ M_{H_2O_2}=2+32=34\ g/mol \\ M_{Cu(OH)_2}=66+32+2=100\ g/mol \\ M_{Al_2S_3}=54+96=150\ g/mol \\ [/tex]
$M_{H_2CO_3}=2+12+48=62\ g/mol \\ M_{AlCl_3}=27+106.5=133.5\ g/mol \\ M_{P_2O_5}= 62+80=142\ g/mol$