Question

Calculati media aritmetica a numerelor: a)0,15; 0,3; 1,11; b) x=1,5*10^3-0,14*10^4; y=(0,3)^2*100-1.

Answer 1

$a)m_{a}=(0.15 + 0.3 + 1.11) \div 3 = 1.56 \div 3 = 0.52$

$b)x = 1.5 \times {10}^{3} - 0.14 \times {10}^{4}$

$x = 1.5 \times 1000 - 0.14 \times 10000$

$x = 1500 - 1400$

$x = 100$

$y = {0.3}^{2} \times 100 - 1$

$y = 0.09 \times 100 - 1$

$y = 9 - 1$

$y = 8$

$m_{a} = (x + y) \div 2$

$m_{a} = (100 + 8) \div 2$

$m_{a} = 108 \div 2$

$m_{a} = 54$