Question

Calculati media aritmetica a numerelor : a=0,7 x (9,5-2) , b=. 3 supra 20 din 400 , c=1,1 la puterea a doua - 23 supra 50. . Dau coroana !!

Answer 1

$\bold{M_a= \frac{a+b+c}{3} } \\ a=0,7 \cdot (9,5-2) =0,7 \cdot 7,5 \\ \Rightarrow \bold{a=5,25}; \\ b= \frac{3}{20} \ din \ 400= \frac{3}{20} \cdot 400= \frac{1200}{20} \\ \Rightarrow \bold{b=60}; \\ c=(1,1)^2- \frac{23}{50} =1,1 \cdot 1,1- \frac{23}{50} =1,21-0,46 \\ \Rightarrow \bold{c=0,75}; \\ M_a= \frac{5,25+60+0,75}{3}= \frac{65,25+0,75}{3} = \frac{66}{3}^{(3}= \frac{22}{1} \\ \Rightarrow \boxed{M_a=22}.$