Question

Calculati media aritmetica a numerelor: a) 13; 5 intergi si 1 supra 4; 2 intregi si 3 supra 4; b) 4,49; 7 intregi si 1 supra 20; 5 intregi si 1 supra 2; c)
32 de intregi si 7 supra 9; 5 intregi si 5 supra 9; 15, (6); d) 0,015; 3,475; 2,11; 12; 74,5 e) 7,(6); 0,(7); 81,(5)

Answer 1

a) (13+ 5 intregi si 1/4+ 2 intregi si 3/4) /3=(13+21/4+11/4)/3=(13+32/4)/3=
=(13+8)/3=21/3=7

b) (4,49 + 7 intregi si 1/20 + 5 intregi si 1/2)/3=
= (449/100 + 141/20 + 11/2)/3=
=[(449+141*5+11*50)/100]/3=1704/300=5,68

c) (32 intregi si 7/9+5 intregi si 5/9+ 15, (6))/3=
=[(295/9+50/9+(156-15)/9]/3=
=(345/9+141/9)/3=
=486/27=18

d) (0,015+ 3,475+ 2,11+ 12+ 74,5)/5=
= (3,49+14,11+74,5)/5=
=92,1/5=18,42

e) [7,(6)+ 0,(7)+ 81,(5)]/3=
=[(76-7)/9+7/9+(815-81)/9]/3=
=(69/9+7/9+734/9)/3=
=(810/9)/3=
=90/3=30