Question

Calculati media aritmetica a numerelor:a)1supra 12,3supra 16 si7 supr
a24

Answer 1

aducem la acelasi numitor comun
$( \frac{4}{48} + \frac{9}{48} + \frac{14}{48} ) \div 3 \\ \\ \frac{27}{48} \div \frac{3}{1} = \frac{27}{48} \times \frac{1}{3} = \frac{9}{48} simplificam cu 3 = \frac{3}{16}$