Question

calculati media aritmetica a numerelor a) 2x 5x 11x b)21x 37x 32x dau coronita și pun punctaj 73 e maxim

Answer 1

Banuiesc ca au bara deasupra (x=cifra):

a)

(2x+5x+11x)/3=(20+x+50+x+100+10+x)/3=(180+3x)/3=60+x=6x(cu bara)

b)

(21x+37x+32x)/3=(200+10+x+300+70+x+300+20+x)/3=

(900+3x)/3=300+x=30x(cu bara)

Fara bara (x=factor):

a) (2*x+5*x+11*x)/3=18*x/3=6*x

b) (31*x+37*x+32*x)/3=90*x/3=30*x