Question

Calculati media aritmetica a numerelor:
a)7,8,36
b)20,81,103
c)12345,21,675
d)2x,4x,5x,9x
e)12,14,16 si 18
f)80,43 si 66
Va rog ajutati-ma

Answer 1

[tex] m_{a} = \frac{a+b}{2}\\ a) m_{a} = \frac{7+8+36}{3}= \frac{51}{3}=17\\ b) m_{a} = \frac{20+81+103}{3}= \frac{204}{3}=68\\ c) m_{a} = \frac{12345+21+675}{3}= \frac{13041}{3}=4347\\ d) m_{a} = \frac{2x+4x+5x+9x}{4}= \frac{20x}{4}=5x\\ e) m_{a} = \frac{12+14+16+18}{4}= \frac{60}{4}=15\\ f) m_{a} = \frac{80+43+66}{3}=\frac{189}{3}= 63[/tex]

Answer 2

(7+8+36)/3=51/3=17
(20+81+103)/3=204/3=68
(12345+21+675)/3=13041/3=4347
(2x+4x+5x+9x)/4=20/4=5
(12+14+16+18)/3=60/3=20
(80+43+66)/3=189/3=63