Question

Calculati media aritmetica a numerelor a si b
a=5supra3 minus 3 supra 7 si

b=1supra3+3 supra7

Ajutor!!!
Multumesc!!

Answer 1

a = $\frac{5}{3}- \frac{3}{7} = \frac{35-9}{21} = \frac{26}{21}$

b = $\frac{1}{3} + \frac{3}{7} = \frac{7+9}{21} = \frac{16}{21}$

Media aritmetica = $\frac{a+b}{2}$
 
a+ b = $\frac{26}{21}+ \frac{16}{21} = \frac{16+26}{21} = \frac{42}{21}=2$

$\frac{a+b}{2} = \frac{2}{2} =1$

Answer 2

a=5 supra 3 - 3 supra 7
a=35 supra 21-9 supra 21
a=26 supra 21
b=1 supra 3+3 supra 7
b=7 supra 21+9 supra 21
b=16 supra 21
(26 supra 21+16 supra 21):2=42 supra 21:2=21 supra 21=1 intreg deorece linia de fractie arata  impartire si daca impartim 21 la 21 va iesi 1 intreg