Question

calculați media aritmetica a trei numere știind că: n-a=c-b, iar b=24,37 ​

Answer 1

m-a=c-b

m=(a+b+c)/3

(a+b+c)/3-a=c-b

b=24,37

(a+24,37+c)/3-a=c-24,37

(24,37+c)/3=c-24,37

(2437/100+c)/3=c-2437/100

[(2437+100c)/100]/3=c-2437/100

(2437+100c)/300=c-2437/100

2437+100x=300c-7311

100c-300c= -7311-2437

-200c= -9748

c=2437/50

c=48,74

(a+b+c)/3-a=c-b

(a+24,37+48,74)/3-a=48,74-24,37

(a+73,11)/3-a=24,37

[(100a+7311)/100)/3]-a=2437/100

(100a+7311)/300-a=2437/100

100a+7311-300a=7311

-200a=0

a=0

m=(a+b+c)/3

m=(0+24,37+48,74)/3

m=73,11/3

m=24,37

Răspuns:

• a=0
• b=24,37
• c=48,74
• m=24,37