Question

calculati media aritmetica ponderata a numerelor 0,(6) si 2,(6) cu ponderile 3 si 6
a numerelor 3,5 Si 2,4 cu ponderile 4 si 5​

Answer 1

0.(6)=6/9=2/3

2.(6)=(26-2)/9=24/9=8/3

Mp=(n1×p1+n2×p2)/(p1+p2), unde n1 si n2 sint numerele ce au ponderile p1 si p2.

n1=0.(6)=2/3

n2=2.(6)=8/3

p1=3

p2=6

mp=(2/3×3+8/3×6)/(3+6)=(2+16)/9=18/9=2

n1=3.5

n2=2.4

p1=4

p2=5

mp=(3.5×4+2.4×5)/(4+5)=(14+12)/9=26/9