Question

calculati media aritmetica ponderata a numerelor 4,5 3,25 si 11,8(3) care au respectiv ponderile x si
x+2 si x+4 stiind ca suma ponderilor este 12
DAU CORONITA !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

Daca suma ponderilor x+(x+2)+x+4=12 ⇒ 3x+6=12 ⇒ 3x=6 ⇒ x=2 si  
Map=[4,5·x+3,25(x+2)+11,8(3)·(x+4)]/[x+(x+2)+(x+4)] ⇒  
Map=[4,5·2+3,25(2+2)+11,8(3)·(2+4)]/12=[9+13+11,8(3)·6]/12=  
=[22+11,8(3)·6]/12={22+11intregi si [(83-8)/90]·6}=[22+11 intregi si (75/90)·6]/12=[22+11 intregi si (5/6)·6]/12=[22+(71/6)·6]/12=(22+71)/12=   
 93/12=31/4