Question

Calculati media aritmetica ponderata a numerelor: 4,5. 3,25 si 11,8(3) care au respectiv ponderile x; x+2 si x+2 si x+4 stiind ca suma ponderilor este 12. va rog ajutati-ma

Answer 1

 [tex] m_p=\frac{4,5*x+3,25*(x+2)+11,8(3)*(x+4)}{12}=...\\ (1)... transform\u{a}m\; frac\c{t}iile\;zecimale ...\\ 4,5=\frac{45^{(5}}{10}=9/2 \;;\;3,25=\frac{325^{(25}}{100}=13/4\;;\\ 11,8(3)=\frac{1183-118}{90}=\frac{1065^{(15}}{90}=71/6\;;\\ \rightarrow\;m_p=\frac{9x/2+13x/4+13/2+71x/6+71*2/3}{12}= ...[/tex]