Question

Calculaţi media aritmetică ponderată a numerelor:a)1/3;1/6;3/8 cu ponderile 2;3 şi respectiv 4.b)0,5; 1,12; 3,2; 4 cu ponderile 3;4;5 şi respectiv 8.

Answer 1

$a)M.aritm.pond.= \frac{2* \frac{1}{3}+3* \frac{1}{6} +4* \frac{3}{8} }{2+3+4} = \frac{ \frac{2}{3} + \frac{1}{2} + \frac{3}{2} }{9} = \frac{4+3+9}{54} = \frac{16}{54} = \frac{8}{27}$

$b)M.aritm.pond.= \frac{3*0,5+4*1,12+5*3,2+8*4}{3+4+5+8} = \frac{1,5+4,48+16+32}{20} = \frac{53,98}{20}$