Question

Calculati media aritmetica si media geometrica a numerelor
a) 12 si 3
b)(radical din2) si (radical din 8)​

Answer 1

Răspuns:

$a) \: \\ m \: a = \frac{12 + 3}{2} = \frac{15}{2} = \bf\orange7,5$

$m \: g = \sqrt{12 \times 3} = \sqrt{36} = \bf\purple6$

$b) \: \\ m \: a = \frac{ \sqrt{2} + \sqrt{8} }{2} = \frac{ \sqrt{2} + 2 \sqrt{2} }{2} = \bf\red{\frac{3 \sqrt{2} }{2} }$

$m \: g = \sqrt{ \sqrt{2} \times \sqrt{8} } = \sqrt{ \sqrt{16} } = \sqrt{4} =\bf\blue 2$

Explicație pas cu pas:

$\bf\green{\boxed{m\:a\:=\frac{x+y}{2} ; \:\:\: m\:g\:=\sqrt{x\times\:y}}}$

Answer 2

Răspuns:

Explicație pas cu pas:

a)

$m_{a} = \dfrac{12+3}{2} = \dfrac{15}{2} =\bf 7,5$

$m_{g} = \sqrt{12 \cdot 3} = \sqrt{36} = \sqrt{6^{2} } =\bf 6$

b)

$m_{a} = \dfrac{\sqrt{2} +\sqrt{8}}{2} = \dfrac{\sqrt{2} + 2\sqrt{2}}{2} =\bf \dfrac{3\sqrt{2}}{2}$

$m_{g} = \sqrt{\sqrt{2} \cdot \sqrt{8}} = \sqrt{\sqrt{2 \cdot 8}} = \sqrt{\sqrt{16}} = \sqrt{\sqrt{4^{2} }} = \sqrt{4} = \sqrt{2^{2} } =\bf 2$