Question

Calculati media aritmetica si media geometrica pentru numerele a=2+radical din3 si b=2-radical din 3

Answer 1

[tex]ma=\dfrac{2+\sqrt{3}+2-\sqrt{3}}{2}=2\\ mg=\sqrt{(2-\sqrt{3})(2+\sqrt{3})}=\sqrt{4-3}=1[/tex]

Answer 2

[tex]Ma= \frac{2+\sqrt{3} +2- \sqrt{3} }{2} = \frac{4}{2} =2 MG= \sqrt{(2+ \sqrt{3})(2- \sqrt{3})}= \sqrt{4-2 \sqrt{3}+2 \sqrt{3}- \sqrt{9} }= \sqrt{4-3} =1 [/tex]