Question

calculati media geometrica a nr 2,4 si 3,(3)
coroana

Answer 1

Răspuns: atasat mai jos

Answer 2

Explicație pas cu pas:

$3.(3) = \frac{33 - 3} {9} = \frac{30}{9} = \frac{10}{3} =3.3 \\ mg = \sqrt{a \times b} \\ \sqrt{2.4 \times 3.3} = \sqrt{ \frac{24}{10} } \times \frac{10}{3} = \sqrt{ \frac{240}{30} } = \sqrt{8}$

$\sqrt{8} = 2 \sqrt{2}$