Question

Calculați media geometrică a numerelor:3radical3-2 si 3radical3+2!!! Va rog

Answer 1

Mg=√(3√3-2)(3√3+2)=√9*3-4=√27-4=√23=4,796

Answer 2

$\frac{(3 \sqrt{3}-2 )+(3 \sqrt{3} +2) }{2} =\ \textgreater \ \frac{3 \sqrt{3}-2+3 \sqrt{3}+2}{2} =\ \textgreater \ \frac{ 6\sqrt{3} }{2} =\ \textgreater \ 3 \sqrt{3}$≈$5,19615$
$(3 \sqrt{3} -2)(3 \sqrt{3} +2)=\ \textgreater \ 9*3-4=\ \textgreater \ 27-4=\ \textgreater \ 23$
am scris doua deoarece nu sunt sigur daca-i "+" sau"-" ....
$Succes$