Question

Calculati media geometrica a numerelor a=(1-√3)(√5+2) si b=(2-√5)(√3+1)

Answer 1

mg=√axb=√(1-√3)(√5+2)x(2-√5)(√3+1)
⇒√(1-√3)(1+√3)(2+√5)(2-√5)=√(1²-√3²)(2²-√5²)=√(1-3)x(4-5)=√(-2)x(-1)=√2

Answer 2

                     [tex]a=(1- \sqrt{3} )*( \sqrt{5} +2)\\ b=(2- \sqrt{5}) * (\sqrt{3} +1)\\ M_g(a;b)= \sqrt{a*b} \\ ~~~~~~~~~~~~= \sqrt{(1- \sqrt{3}* \sqrt{5}+2)* (2- \sqrt{5} * \sqrt{3} +1) }\\ ~~~~~~~~~~~~= \sqrt{2} [/tex]