Question

Calculati media geometrica a numerelor a si b :

Answer 1

Răspuns:

Bună,

$a = \sqrt{12} - 2 \sqrt{27} + 5 \sqrt{3} + \sqrt{48} + 2 \sqrt{75} \\ a = 2 \sqrt{3} - 6 \sqrt{3} + 5 \sqrt{3} + 4 \sqrt{3} + 10 \sqrt{3} \\ a = 15 \sqrt{3}$

$b = \sqrt{(5 - \sqrt{3}) ^{2} } - \sqrt{(2 \sqrt{3} - 3 \sqrt{2})^{2} } - \sqrt{(5 - 3 \sqrt{2}) ^{2} } + \sqrt{7 ^{2} - 1 ^{2} } \\ b = 5 - \sqrt{3} - (3\sqrt{2} - 2\sqrt{3} ) - (5 - 3 \sqrt{2} ) + \sqrt{49 - 1} = \\ 5 - \sqrt{3} - 3 \sqrt{2} + 2 \sqrt{3} - 5 + 3 \sqrt{2} + \sqrt{48} \\ \sqrt{3} + 4 \sqrt{3} = \\ 5 \sqrt{3}$

$m.g = \sqrt{a \times b}$

$m.g = \sqrt{15 \sqrt{3} \times 5 \sqrt{3} } = \\ \sqrt{15 \times 5 \times 3} = \\ \sqrt{225} = \\ 15$

Sper că te-am ajutat