Question

Calculati media geometrica a numerelor a si b , unde : a=√50+√72+3√18-√98-2√32 si b=0,(3).12√8-(5 supra √2+21 supra √18-99 supra √242):0,5

Answer 1

√50=5√2
√72=6√2
3√18=9√2
√98=7√2
2√32=8√2
a=5√2+6√2+9√2-7√2-8√2
a=5√2

0,(3)·12√8=3/9·24√2=1/3·24√2=simplif cu 3=8√2
5/√2=5√2/2
21/√18=21/3√2=21√2/6=simplif.cu 3=7√2/2
99/√242=99/11√2=99√2/22=simplif cu 11=9√2/2
0,5=5/10=simplif cu 2=1/2
b=8√2-(5√2/2+7√2/2-9√2/2):1/2
b=8√2-3√2/2·2/1
b=8√2-3√2
b=5√2
Mg=√a·b=√(5√2·5√2)=√(5√2)²=5√2
Mg=5√2