Question

Calculati media geometrica a numerelor reale:
a) √30-12√6-√4+2√3+3√5-2√6+5
b)2√8-√14+4√6-√22+4√10

Answer 1

$a= \sqrt{30}-12 \sqrt{6}- \sqrt{4}+2 \sqrt{3}+3 \sqrt{5}-2 \sqrt{6} +5$
$a= \sqrt{30}-12 \sqrt{6}+2 \sqrt{3}+3 \sqrt{5}-2 \sqrt{6} +3$
$a= \sqrt{30}-14\sqrt{6}+2 \sqrt{3}+3 \sqrt{5} +3$

$b=2\sqrt{8}- \sqrt{14}+4 \sqrt{6}- \sqrt{22} +4+ \sqrt{10}$
$b=2*(2 \sqrt{2} )- \sqrt{14}+4 \sqrt{6}- \sqrt{22} +4+ \sqrt{10}$
$b=4 \sqrt{2} - \sqrt{14}+4 \sqrt{6}- \sqrt{22} +4+ \sqrt{10}$

$m_g= \sqrt{a*b}$
$m_g= \sqrt{(\sqrt{30}-14\sqrt{6}+2 \sqrt{3}+3 \sqrt{5} +3)*(4 \sqrt{2} - \sqrt{14}+4 \sqrt{6}- \sqrt{22} +4+ \sqrt{10})}$
De aici cred ca te descurci ;)