Question

Calculați media geometrică a numerelor reale pozitive a și b:​

Answer 1

Formula mediei geometrice $\boxed{Mg = \sqrt{a*b} }$

a) $Mg = \sqrt{2*18} =\sqrt{36}=\sqrt{6^2} =6$

b) $Mg = \sqrt{3*12}=\sqrt{36}=6$

c) $Mg=\sqrt{\frac{14}{5}*\frac{10}{7} }=\sqrt{2*2 }=\sqrt{4} =2$

d) $Mg = \sqrt{112*\frac{4}{7}}=\sqrt{16*4} =\sqrt{64}=8$

e) $Mg = \sqrt{1,2*3,(3) }=\sqrt{\frac{12}{10}*\frac{33-3}{9} }=\sqrt{\frac{6}{5} *\frac{30}{9} }=\sqrt{\frac{6}{5} *\frac{10}{3} } =\sqrt{2*2} =\sqrt{4} =2$