Question

Calculati media geometrica a numerelor reale pozitive:
x=$\frac{\sqrt{3} -1}{1+\sqrt{3} }$ si
y=$\frac{2}{9}(4+ \frac{6}{ \sqrt{3} } )$
Multumesc mult!

Answer 1

x=(√3-1)/(1+√3)=(√3-1)(√3-1)/(√3+1)(√3-1)=(3-2√3+1)/(3-1)=(4-2√3)/2= =2(2-√3)/2=2-√3
y=2/9 (4+6/√3)=2/9 (4+6√3/3)=2/9 (4+2√3)=4(2+√3)/9
mg=√x×y=√(2-√3)×4(2+√3)/9=√4(4-3)/9=√4/9=2/3