Question

calculati media geometrica....help​

Answer 1

Explicație pas cu pas:

$m_{g} = \sqrt{ab} = \sqrt{(3 - \sqrt{5} )(3 + \sqrt{5} )} = \sqrt{ {3}^{2} - {( \sqrt{5} )}^{2} } = \sqrt{9 - 5} = \sqrt{4} = 2$

$m_{g} = \sqrt{ab} = \sqrt{(10 - \sqrt{19} )(10 + \sqrt{19} )} = \sqrt{ {10}^{2} - {( \sqrt{19} )}^{2} } = \sqrt{100 - 19} = \sqrt{81} = 9$

$m_{g} = \sqrt{ab} = \sqrt{(12 - 2\sqrt{11} )(12 + 2\sqrt{11} )} = \sqrt{ {12}^{2} - {( 2\sqrt{11} )}^{2} } = \sqrt{144 - 44} = \sqrt{100} = 10$

$m_{g} = \sqrt{ab} = \sqrt{(16 - 2\sqrt{15} )(16 + 2\sqrt{15} )} = \sqrt{ {16}^{2} - {(2 \sqrt{15} )}^{2} } = \sqrt{256 - 60} = \sqrt{196} = 14$

$m_{g} = \sqrt{ab} = \sqrt{(24 - 4\sqrt{11} )(24 + 4\sqrt{11} )} = \sqrt{ {24}^{2} - {(4 \sqrt{11} )}^{2} } = \sqrt{576 - 176} = \sqrt{400} = 20$

$m_{g} = \sqrt{ab} = \sqrt{(27 - 10\sqrt{2} )(27 + 10\sqrt{2} )} = \sqrt{ {27}^{2} - {( 10\sqrt{2} )}^{2} } = \sqrt{729 - 200} = \sqrt{529} = 23$