Question

calculati media ponderala a numerelor: a) 1,(3) si 3/1/3 cu ponderile 3 si respectiv 6; b) 1/2 ;1,3(8) si 0,(3) cu ponderile1,9 si respectiv6

Answer 1

a)
1,(3)=(13-1)/9=12/9=4/3
3 1/3=10/3
(4/3*3+10/3*6)/(3+6)=(4+20)/9=24/9=8/3=2,(6)

b)1,3(8)=(138-13)/90=125/90=25/18
0,(3)=3/9=1/3
(1/2*1+25/18*9+1/3*6)/(1+9+6)=
=(1/2+25/2+2)/16=
=(26/2+2)/16=
=(13+2)/16=15/16=0,9375