Question

Calculati modul de z=(1+3i)/(1+i)
Raspuns pentru liceu clasa a 10-a

Answer 1

z=(1+3i)/(1+i)=(1+3i)(1-i)/(1+i)(1-i)=(1-i+3i-3i²)/1-i²=(1+3+2i)/1+1=(4+2i)/2=2+i
|z|=√(a²+b²)=√(2²+1²)=√(4+1)=√5