Question

Calculati numarul a pentru care 2018(2017-(2017-2×(63 ×a+1)+2017))=1

Answer 1

$2018\{2017-[2017-2\times(63\times a+1)+2017]\}=1\\\\Intai\ impartim\ in\ ambele\ parti\ prin\ 2018.\\\\\frac{2018\{2017-[2017-2\times(63\times a+1)+2017]\}}{2018}=\frac{1}{2018}\\\\2017-[2017-2\times(63\times a+1)+2017]=\frac{1}{2018} \\\\2017-[-2(63a+1)+4034]=\frac{1}{2018}\\\\2017 - (-126a-2+4034)=\frac{1}{2018}\\\\2017 - (-126a+4032)=\frac{1}{2018}\\\\2017+126a-4032=\frac{1}{2018}\\\\126a-2015=\frac{1}{2018}\\\\126a=\frac{1}{2018}+2015\\\\126a=\frac{1+2015\times2018}{2018}$

$\\\\a=\frac{1+2015\times2018}{2018}\times \frac{1}{126}\\\\a=\frac{1+4066270}{2018\times126}\\\\a=\frac{4066271}{254268}$