Question

Calculați numărul atomilor de hidrogen din 2,24L(c.n.) de NH3

Answer 1

$2N_2 + 3H_2 =\ \textgreater \ 2NH_3$
 v amoniac= 2.24 l
n amoniac=2.24 l / 22.4 l/mol = 0.1 mol
3 mol H_{2} .... 2 mol amoniac
a mol H_{2} ....0.1 mol amoniac
a= 0.15 mol H_{2}

nr atomi H = 0.15 mol × $6.022 x 10^{23} atomi/mol$ 
= 9.033 x $10^{22}$