Question

calculati numarul de moli din: 9,033*10(la puterea 23) molecule N2 ; 9,033*10(la puterea 26) molecule NH3

Answer 1

1mol....................6.022*10²³molecule N₂
x moli..................9.033*10²³molecule N₂
x=9.033*10²³*1/6.022=1.5 moli

9.033*10²⁶ =9033*10²³
1mol.........................6.022*10²³molecule NH₃
y moli.......................9033*10²³molecule NH₃
y=9033*10²³*1/6.022*10²³=1500moli