Question

Calculati numarul x=a+(-b),daca:
a=-1,(6)+(+1,75)+(-1,125)
b=-1,1(6)+(+9 supra 8)+[-1,08(3)]

Answer 1

a=-1,(6)+(+1,75)+(-1,125)=-1,041(6)
b=-1,1(6)+(+9 /8)+[-1,08(3)]=-1,1(6)+(+1,125)+[-1,08(3)]=-1,124(9)


x=a+(-b)=[-1,041(9)]+1,124(9)=0,083

Answer 2

$\displaystyle a=-1,(6)+(+1,75)+(-1,125) \\ \\ a=- \frac{16-1}{9} + \frac{175}{100} - \frac{1125}{1000} \\ \\ a=- \frac{15}{9} + \frac{175}{100} - \frac{1125}{1000} \\ \\ a=- \frac{15000}{9000} + \frac{15750}{9000} - \frac{10125}{9000} \\ \\ a=- \frac{9375}{9000} ^{(375} \\ \\a=- \frac{25}{24}$

$\displaystyle b=-1,1(6)+\left(+ \frac{9}{8} \right)+[-1,08(3)] \\ \\ b=- \frac{116-11}{90} + \frac{9}{8} + \left (- \frac{1083-108}{900} \right ) \\ \\ b=- \frac{105}{90} + \frac{9}{8} - \frac{975}{900} \\ \\ b=- \frac{2100}{1800} + \frac{2025}{1800} - \frac{1950}{1800} \\ \\ b=- \frac{2025}{1800} ^{(225} \\ \\ b=- \frac{9}{8}$

$\displaystyle x=a+(-b) \\ \\ x=- \frac{25}{24}+ \left[- \left(- \frac{9}{8} \right ) \right ] \\ \\ x=- \frac{25}{24} + \frac{9}{8} \\ \\ x=- \frac{25}{24} + \frac{27}{24} \\ \\ x= \frac{2}{24} ^{(2} \\ \\ x= \frac{1}{12}$