Question

CALCULATI (ORDINEA EFECTUARII OPERATIILOR CU FRACTII)
(1 intreg 2/3+5/8):(3 intregi 1/8 - 1 intreg 3/12)
30/7*(7 intregi 1/15 + 3 intregi 1/15 - 2 intregi1/3)
3/16*(16/24-5/8)

VA ROG MUUUUUUULT

Answer 1

Răspuns:

Explicație pas cu pas:

->  introduc intregii in fractie:

1 intreg si 2/3 = (1×3+2)/3 = 5/3

3 intregi si 1/8 =(3×8+1)/8 = 25/8

1 intreg si 3/12 =(1×12+3)/12= 15/12 = 5/4

= ( 5/3 + 5/8) : ( 25/8 - 15/12) =

= ( 40/24 + 15/24): ( 25/8 - 5/4) =

= (55/24) : ( 25/8 - 10/8 ) =

= (55/24) : ( 15/8) =

= (55/24) × (8/15) =

= 11/(3×3) =

= 11/9 =

= 1 intreg si 2/9

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7 intregi si 1/15 = (7×15+1)/15 = 106/15

3 intregi 1/15 = ( 3×15+1)/15 = 46/15

2 intregi si 1/3 = (2×3+1)/3 = 7/3

= (30/7) × ( 106/15 + 46/15 - 7/3) =

= (30/7) × ( 152/15 - 35/15) =

= (30/7) × ( 117/15) =

= (2×117)/7 =

= 234/7

= 33 intregi si 3/7

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(3/16) × ( 16/24 - 5/8 ) =

= (3/16) × ( 16/24 - 15/24) =

= (3/16) × (1/24 ) =

= 1/(16×8) =

= 1/128

Answer 2

Răspuns:

$\frac{143}{6770}$

Explicație pas cu pas:

$= (\frac{5}{3} +\frac{5}{8} ):(\frac{25}{8} -\frac{15}{12} )\frac{30}{7} (\frac{106}{15} +\frac{46}{15} -\frac{7}{3} )\frac{3}{16}(\frac{16}{24} -\frac{15}{12} )=(\frac{40}{24} +\frac{15}{24} ):(\frac{75}{24} -\frac{30}{24} )\frac{30}{7} (\frac{106}{15} +\frac{46}{15} -\frac{35}{15} )\frac{3}{16}*\frac{1}{24} =\frac{55}{24}:\frac{45}{24} *\frac{30}{7} (\frac{106}{15} +\frac{11}{15} )\frac{3}{16} *\frac{1}{24}=\frac{55}{24} *\frac{24}{45}*\frac{30}{7} *\frac{117}{15} *\frac{1}{128} =\frac{11}{9} *$$\frac{234}{105} *\frac{1}{128} =\frac{286}{105} *\frac{1}{128} =\frac{286}{13440} =\frac{143}{6770}$

Sper ca  te-am ajutat! Bafta!