Question

Calculati partea reala a numarului complex z= (3+2i)/ (2-3i)

Answer 1

$\frac{(3+2i)(2+3i)}{(2+3i)(2-3i)}= \frac{6+9i+4i-6}{ 2^{2}- (3i)^{2} }= \frac{13i}{4+9}= \frac{13i}{13}=i$

partea reala este 0