Question

CALCULATI PERIMETRUL TRIUNGHIULUI ABC daca A(2√5, 1), B(0,5) si C(3√5, 3)

Cu rezolvare

Answer 1

A(2√5.1).
B(0.5)
C(3√5.3)
P∠ABC?
AB=?
A(3√5.3)
B=(0.5)

AB=√(XB-XA)²+(YB-YA)²=
AB=√(0-3√5)²+(5-3)²=
AB=√(-3√5)²+(2)²⇒
AB=√45+4⇒AB=√49⇒AB=7

BC=?
B(0.5)
C(3√5.3)
BC=√(XC-XB)²+(YC-YB)²⇒
BC=√(3√5-0)²+(3-5)²⇒
BC=√(3√5)²+(-2)²⇒
BC=√45+4⇒BC=√49⇒BC=7

AC=?
A(2√5.1)
C(3√5.3)
AC=√(XC-XA)²+(YC-YA)²
AC=√(3√5-2√5)²+(3-1)²⇒
AC=√(√5)²+(2)²⇒
AC=√5+4⇒AC=√9⇒AC=3
P=SUMA TUTUROR LATURILOR
P=AB+AC+BC⇒
P=7+7+3⇒P=14+3⇒P=17
SUCEES