Question

Calculati perimetrul unui poligon convex cu laturile de: a) 7 intreg si 1 pe 3 cm; 6,(2) cm; 6 cm; 7,(8) cm; va rog mult.

Answer 1

$7 \frac{1}{3} = \frac{7*3+1}{3} = \frac{22}{3}$  cm

$6,(2)= \frac{62-6}{9} = \frac{56}{9}$  cm

6 cm

$7,(8)= \frac{78-7}{9}= \frac{71}{9} cm$


$\frac{22}{3}+\frac{56}{9} +6+\frac{71}{9}= \frac{22*3+56+6*9+71}{9} = \frac{66+56+54+71}{9}= \frac{247}{9} =27,(4) cm$